변환 방법 전력 의 킬로와트 (kW) 를 전류 의 암페어 (A).
킬로와트와 볼트. You can't convert kilowatts 를 amps s의ce kilowatts and amps units do not measure the same quantity.
전류 I 의 amps is equal 를 1000 times the power P 의 kilowatts, divided by the voltage V 의 볼트:
I(A) = 1000 × P(kW) / V(V)
So amps are equal 를 1000 times kilowatts divided by 볼트.
암페어 = 1000 × kilowatts / 볼트
또는
A = 1000 × kW / V
What is the current 의 amps when the power consumption is 0.33 kilowatts and the voltage supply is 110 볼트
I = 1000 × 0.33kW / 110V = 3A
상전류 I 의 amps is equal 를 1000 times the real power P 의 kilowatts, divided by the power fac를r 역률 실효값 전압을 곱한 값 V 의 볼트:
I = 1000 × P / (역률 × V )
So amps are equal 를 1000 times kilowatts divided by power fact또는 times 볼트.
암페어 = 1000 × 킬로와트 / (역률 × 볼트)
또는
A = 1000 × kW / (역률 × V)
What is the phase current 의 amps when the power consumption is 0.33 kilowatts, the power fac를r is 0.8 and the RMS voltage supply is 110 볼트
I = 1000 × 0.33kW / (0.8 × 110V) = 3.75A
상전류 I 의 amps is equal 를 1000 times the real power P 의 kilowatts, divided by square root of 3 times the power fac를r 역률 times the l의e 를 l의e RMS voltage VL-L 의 볼트:
I = 1000 × P / (3 × 역률 × VL-L )
So amps are equal 를 1000 times kilowatts divided by square root of 3 times power fact또는 times 볼트.
암페어 = 1000 × 킬로와트 / (3 × 역률 × 볼트)
또는
A = 1000 × kW / (3 × 역률 × V)
What is the phase current 의 amps when the power consumption is 0.33 kilowatts, the power fac를r is 0.8 and the voltage supply is 110 볼트
I = 1000 × 0.33kW / (3 × 0.8 × 110V) = 2.165A
